3y^2=572

Solution for 3y^2=572 equation:

3y^2=572

We move all terms to the left:

3y^2-(572)=0

a = 3; b = 0; c = -572;
Δ = b2-4ac
Δ = 02-4·3·(-572)
Δ = 6864
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{6864}=\sqrt{16*429}=\sqrt{16}*\sqrt{429}=4\sqrt{429}$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{429}}{2*3}=\frac{0-4\sqrt{429}}{6}
=-\frac{4\sqrt{429}}{6}
=-\frac{2\sqrt{429}}{3}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{429}}{2*3}=\frac{0+4\sqrt{429}}{6}
=\frac{4\sqrt{429}}{6}
=\frac{2\sqrt{429}}{3}
$